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Solution To The Two - Body Problem

2-body-system.png

The center of mass ( barycenter ) will lay along a radial vector radial_vector.png connecting masses m_1.png and m_2.png, where its position, cm.png, along the radial vector lies in exact proportion to the relative amount of mass at each end of the radial vector. That is, the ratios

ratios.png

determine the precise position of center of mass, cm.png, along radial vector radial_vector.png.

Therefore,

vectors.png

which implies that

implies.png.

Now, Newton's force equations acting on m_1.png and m_2.png respectively becomesĀ 

force_vectors.png.

Also, total kinetic energy for an isolated 2 -body system becomes

total_k.e.png

Finally, whenever there is a relatively isolated 2 - body system, there will by definition be no acceleration at barycenter ( center of mass ) since all of the forces balance - i.e.,

isolated_2_body_system.png.

Notice, moreover, that this isolated 2 - body system reduces down as follows:

combined_mass.png.

If, on the other hand, m_2.png is a small mass relative to m_1.png such as an artificial satellite put up around a much larger planet or moon, the above equation for combined mass indicates that the barycenter of the 2 - body system effectively becomes the center of mass of the much larger mass body !




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